5x^2-4x=17

Solution for 5x^2-4x=17 equation:

5x^2-4x=17

We move all terms to the left:

5x^2-4x-(17)=0

a = 5; b = -4; c = -17;
Δ = b2-4ac
Δ = -42-4·5·(-17)
Δ = 356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{356}=\sqrt{4*89}=\sqrt{4}*\sqrt{89}=2\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{89}}{2*5}=\frac{4-2\sqrt{89}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{89}}{2*5}=\frac{4+2\sqrt{89}}{10}
$